oxycodone

kjb45 · Oct 7, 2010

14-Hydroxycodeinone -> Oxycodone
Next is to reduce that double bond which is VERY EASY if you have a source of hydrogen. As far as other equipment, you need two syringes with the plunger removed and needles attached. To each you attach a balloon the the plunger end. Then, you need some sort of thick rubber to cover the mouth of your flask, but can be penetrated (air tight) by your needles. Ok, so you throw in like 3 molar % (of initial moles of codeine) of Pd/C (either 10% or 5% Pd on Carbon) into your flask which contains your goodies in a fairly concentrated solution of ~8% acetic acid in MeOH (Not super concentrated, but definately not super dilute) with STIRRING. Then you fill your ballons through the needles, purge your flask air space with hydrogen by inserting both needles through the rubber diaphram and insert a third needle to allow an out flow. After it has purged for a while pull out the purge needle and make sure that the hole it created is now sealed. Refill your balloons and reinsert them. Let it stir overnight. I have done this on a few gram scale so there wasn't a lot of hydrogen absorbed. If you were doing a tens of grams scale, you would need to refill the balloons several times during the reaction or you may still need to do this if you have bad leaks. Ok, so filter your solution. It's about the same color, maybe a little bit lighter, but don't worry cuz it worked. Again, basify, shake with chloroform and extract 3x. Evaporate, disolve in acetone and gas or drip in HCl to crystalize. Your crystals may turn to goo when exposed to air during filtration if you use wet HCl. Don't worry about it, just realize you are gonna have to drip an aqueous oxy solution into your nose instead of getting to snort bumps to get high. Do not over acidify during crystalization! When your solution turns from brown to clear, stop adding acid and filter. If you overacidify, your crystals will turn to brown goo balls in your flask. They won't be destroyed but if you dried and snorted 'em the leftover HCl's might burn your nose a bit.
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here is a nice synthesis of oxycodone but i dont understand a sentence as i am not a chemist:"Ok, so you throw in like 3 molar % (of initial moles of codeine) of Pd/C (either 10% or 5% Pd on Carbon)"
can someone help me to understand please?

pharfromit · Oct 8, 2010

Yeah that doesn't really make sense because what is the molecular weight of Pd/C, say 10 or 20C to 1Pd, sum, okay that is easy enough. Then just use 3% of the mole equivalence to the amound of codeine. Thats my best guess. No one should attempt this especially if all they have to go off of is said recipe.

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oxycodone

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