My 'calculator Discovery' (And No One Believes Me).

Nothing, his calculator does not understand true infinity.
The "anomaly" will will only show up if the repeating number is broken.
The square root of 0.111... is 0.333... forever, to infinity.

But the square root of
0.11111111111111111111111111111111111111110_
is actually
0.333333333333333333333333333333333333333316666666666249999
it just simply is.

 

I am starting to feel trapped. How do I get out of these numbers?

 

i hate numbers
boy do I hate numbers
please leave me be
in color's destiny


what?

 

I don't know
I just write the shit

 

Are you talking to yourself again, Moonglow?

 

I argue that if any number greater than zero is divided by zero, the result should be infinity, since the numerator can be divided into infinite portions of zero

 

I would say i was...i am pretty cool to talk to....

 

the solution is undefined or NaN because 1/0 cannot be infinity and there is a very good reason...

any number multiplied by 0 == 0 ... infinity times zero is still zero, not 1.

which means division by zero would be irreversible, so it can't be done.

 

https://www.youtube.com/watch?v=eSBybJGZoCU

 

Think of a number, divide it by two
Something is nothing, nothing is nothing
Open a box, tear off the lid
Then think of a number, don't think of an answer
Open your eyes, think of a number
Don't get swept under, a number's a number
A chance encounter you want to avoid the inevitable
So you do, oh yes you do the impossible
Now you ain't got a number, you just want to rhumba
And there ain't no way you're gonna go under
Go under, go under, go under, go under
You tell me asunder
Go under, go under, go under, yeah

 

Not to mention it violates other rules, from a more physics-based standpoint. Dividing by zero would be the equivalent of destroying energy/mass in such a setting. Doesn't make sense whatsoever.

 

Conoco.

 

the pattern the OP is seeing the result of the approximation of 1/9 being off by

∞
∑ 10^-n
n=k+1

where k is the number of decimal places in the approximation.

so ..... what you have is actually

1 ∞
− - ∑ 10^0-n
9 n=k+1

if you take the square root of that entire expression it approximates the first expression. add them together and you should get 1/9 proper.