order of operations parenthesis exponents multiply divide add subtract. thats the order in which you are to calculate.
Equals is not an operation. It is an equivilance relationship. The PEMDAS system is a convention that was established so that each side of an equation could be substitiuted freely for the other side.
a = x [a's and x's] a+a = a+x [add a to both sides] 2a = a+x [a+a = 2a] 2a-2x = a+x-2x [subtract 2x from both sides] 2(a-x) = a+x-2x [2a-2x = 2(a-x)] 2(a-x) = a-x [x-2x = -x] 2 = 1 [divide both sides by a-x] in between lines 2 and 3 of the equation, a+a mysteriously turns into 2a. you cannot do that
yes you can, man you know shit about math lets make it simple 5+5=10 2*5=10 tada and btw i posted the solution long ago so THREAD CLOSED
death, theyre right, the system you are using is totally thrown out the window when you look at algebra past grade 10. as for this question, its a tricky one, but you cant divide by 0. the correct term for 'infinity' is 'indefinable' which is exactly what dividing by 0 is. all things divided by 0 are infinite, and thus cannot be defined from eachother. thus they are indefinable, and THUS you cant put an equals sign in front of them.
just because you dont find much worthwhile in mathematics doesnt mean that these sorts of issues havnt DEFINED THE WORLD YOU LIVE IN. mathematics is the only stable thing in the universe. this is because we have defined it AS stability. there are no recordable relationships that are not based on mathematical principles on their most fundamental level. whether YOU care about them or not has no value in determining how worthwhile their study is. what exactly are you suggesting that mathematicians cannot do, but teach? maths is what they do. you cant do it on most levels. and you probably couldnt teach it either.
i need to see some proof that you can just change operations whenever you want, just because they are equal.
It can't be done. Your desire for that certainty is understandable, but unattainable. The core of the problem is an axiom of symbolic logic. What you are looking for is the Axiom Schema of replacement which says that if A is a well formed formula (wff) with a free variable x, then the replacement of every instance of x with a wff B, in which x does not appear, is a wff. This is an axiom and, hence, unprovable.
the core of the problem is notunderstanding what '+' and 'x' mean. it is a fundamental rule that 2a = a + a, 5a = a+a+a+a+a just like a^2 = a x a , a^5 = a x a x a x a x a this is what the symbols were invented for, so that each article in subject does not have to be rewritten
It seems that Death does not understand that axioms and definitions are unprovable. If he is serious, he will follow the same path that Hilbert, Cantor, and Russell did.